Questions: Question 2
Using the equation y=12x+7, solve for y, if x=3
y=
43
22
17
18
Question 3
Using the equation y=12x+7, solve for x, if y=67
X=
5
Transcript text: Question 2
2. Using the equation $y=12 x+7$, solve for $y$, if $x=3$
$y=$ $\qquad$
43
22
17
18
Question 3
3. Using the equation $y=12 x+7$, solve for $x$, if $y=67$
$\mathrm{X}=$ $\qquad$
5
Solution
Solution Steps
To solve these questions, we will use the given linear equation \( y = 12x + 7 \).
Question 2
To find \( y \) when \( x = 3 \), substitute \( x \) with 3 in the equation and solve for \( y \).
Question 3
To find \( x \) when \( y = 67 \), substitute \( y \) with 67 in the equation and solve for \( x \).
Step 1: Solve for \( y \) when \( x = 3 \)
Given the equation \( y = 12x + 7 \), substitute \( x = 3 \):
\[
y = 12(3) + 7 = 36 + 7 = 43
\]
Step 2: Solve for \( x \) when \( y = 67 \)
Given the equation \( y = 12x + 7 \), substitute \( y = 67 \) and solve for \( x \):
\[
67 = 12x + 7
\]
Subtract 7 from both sides:
\[
60 = 12x
\]
Divide both sides by 12:
\[
x = \frac{60}{12} = 5
\]