Questions: Solve the equation for exact solutions over the interval [0,2π).
2 cot x + 1 = -1
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is .
(Type an exact answer, using π as needed. Type your answer in radians. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)
B. The solution is the empty set.
Transcript text: Solve the equation for exact solutions over the interval $[0,2 \pi)$.
\[
2 \cot x+1=-1
\]
Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is $\square$ \}.
(Type an exact answer, using $\pi$ as needed. Type your answer in radians. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed.)
B. The solution is the empty set.
Solution
Solution Steps
Step 1: Isolate the Trigonometric Function
We start with the equation:
2cotx+1=−1
Rearranging gives:
2cotx=−2
Thus, we have:
cotx=−1
Step 2: Convert to Tangent
Using the identity cotx=tanx1, we can rewrite the equation as:
tanx1=−1
This leads to:
tanx=−1
Step 3: Find Solutions in the Interval
The solutions to tanx=−1 occur at:
x=43πandx=47π
These angles are within the interval [0,2π).