Questions: For a standard normal distribution, find: P(z>2.27) Express the probability as a decimal rounded to 4 decimal places.

For a standard normal distribution, find:
P(z>2.27)

Express the probability as a decimal rounded to 4 decimal places.
Transcript text: For a standard normal distribution, find: \[ \mathrm{P}(z>2.27) \] Express the probability as a decimal rounded to 4 decimal places. Question Help: Video 1 Video 2
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Solution

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Solution Steps

Step 1: Define the Problem

We need to find the probability \( P(z > 2.27) \) for a standard normal distribution. This can be expressed using the cumulative distribution function \( \Phi(z) \) as follows:

\[ P(z > 2.27) = 1 - P(z \leq 2.27) = 1 - \Phi(2.27) \]

Step 2: Calculate the Cumulative Probability

Using the properties of the cumulative distribution function, we can express the probability as:

\[ P(z > 2.27) = \Phi(\infty) - \Phi(2.27) \]

Where \( \Phi(\infty) = 1 \) since the cumulative probability approaches 1 as \( z \) approaches infinity.

Step 3: Evaluate the Cumulative Probability

From the calculations, we find:

\[ P(z > 2.27) = 1 - \Phi(2.27) = 0.0116 \]

Final Answer

Thus, the probability that \( z \) is greater than 2.27 is:

\[ \boxed{0.0116} \]

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