Questions: A commercial mouthwash contains 5.00 g of ethanol and 0.034 g of antiseptic in each 50 mL portion. Calculate the weight/volume percent concentration for each component. Be sure each of your answer entries has the correct number of significant figures. Part 1 of 2 % (weight/volume) ethanol 10

Solution Steps

We need to calculate the weight/volume percent concentration for ethanol and antiseptic in a mouthwash solution. The weight/volume percent concentration is defined as the mass of the solute (in grams) per 100 mL of solution.

The formula for weight/volume percent concentration is:

\[ \text{Weight/Volume \%} = \left( \frac{\text{mass of solute (g)}}{\text{volume of solution (mL)}} \right) \times 100 \]

For ethanol:

• Mass of ethanol = 5.00 g
• Volume of solution = 50.0 mL

Substitute these values into the formula:

\[ \text{Weight/Volume \% of Ethanol} = \left( \frac{5.00 \, \text{g}}{50.0 \, \text{mL}} \right) \times 100 = 10.0\% \]

For antiseptic:

• Mass of antiseptic = 0.034 g
• Volume of solution = 50.0 mL

Substitute these values into the formula:

\[ \text{Weight/Volume \% of Antiseptic} = \left( \frac{0.034 \, \text{g}}{50.0 \, \text{mL}} \right) \times 100 = 0.068\% \]

Final Answer