Questions: Find the x - and y-intercepts for the function. f(x) = (x+6)/(x^2+4) Enter your answers as points, (a, b). The x-intercept is The y-intercept is

Find the x - and y-intercepts for the function.
f(x) = (x+6)/(x^2+4)

Enter your answers as points, (a, b).

The x-intercept is 

The y-intercept is
Transcript text: Find the $x$ - and $y$-intercepts for the function. \[ f(x)=\frac{x+6}{x^{2}+4} \] Enter your answers as points, $(a, b)$. The $x$-intercept is $\square$ The $y$-intercept is $\square$
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Solution

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Solution Steps

To find the $x$-intercept, we need to set $f(x) = 0$ and solve for $x$. For the $y$-intercept, we need to evaluate $f(0)$.

Solution Approach
  1. To find the $x$-intercept, set the numerator of the function equal to zero and solve for $x$.
  2. To find the $y$-intercept, substitute $x = 0$ into the function and solve for $f(0)$.
Step 1: Finding the \( x \)-intercept

To find the \( x \)-intercept, we set the function \( f(x) \) equal to zero: \[ f(x) = 0 \implies \frac{x + 6}{x^2 + 4} = 0 \] This occurs when the numerator is zero: \[ x + 6 = 0 \implies x = -6 \] Thus, the \( x \)-intercept is the point: \[ (-6, 0) \]

Step 2: Finding the \( y \)-intercept

To find the \( y \)-intercept, we evaluate the function at \( x = 0 \): \[ f(0) = \frac{0 + 6}{0^2 + 4} = \frac{6}{4} = \frac{3}{2} \] Thus, the \( y \)-intercept is the point: \[ (0, \frac{3}{2}) \]

Final Answer

The \( x \)-intercept is \(\boxed{(-6, 0)}\) and the \( y \)-intercept is \(\boxed{(0, \frac{3}{2})}\).

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