Questions: Two hours after the start of a 100-kilometer bicycle race, a cyclist passes the 02-kilometer mark while riding at a velocity of 45 kilometers per hour. Complete parts (A) through (C) below. (A) Find the cyclist's average velocity during the first two hours of the race. kilometers per hour

Solution Steps

We are given that a cyclist passes the 62-kilometer mark two hours after the start of a 100-kilometer race. We need to find the cyclist's average velocity during the first two hours of the race.

The average velocity \( v_{\text{avg}} \) over a time interval is given by the formula:

\[ v_{\text{avg}} = \frac{\Delta s}{\Delta t} \]

where \(\Delta s\) is the change in position (displacement) and \(\Delta t\) is the change in time.

• The displacement \(\Delta s\) is the distance covered in the first two hours, which is 62 kilometers.
• The time interval \(\Delta t\) is 2 hours.

Substitute these values into the formula:

\[ v_{\text{avg}} = \frac{62 \text{ km}}{2 \text{ hr}} = 31 \text{ km/hr} \]

Final Answer