Questions: The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. What is this distance in millimeters? 1.15 × 10^-8 mm 1.15 × 10^-7 mm 1.15 × 10^13 mm 1.15 × 10^17 mm

The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. What is this distance in millimeters?
1.15 × 10^-8 mm
1.15 × 10^-7 mm
1.15 × 10^13 mm
1.15 × 10^17 mm

Transcript text: The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. What is this distance in millimeters? $1.15 \times 10^{-8} \mathrm{~mm}$ $1.15 \times 10^{-7} \mathrm{~mm}$ $1.15 \times 10^{13} \mathrm{~mm}$ $1.15 \times 10^{17} \mathrm{~mm}$

Solution

Solution Steps

Step 1: Understanding the Conversion Factor

To convert the distance from picometers (pm) to millimeters (mm), we need to know the conversion factor between these units.

1 picometer (pm) is equal to $10^{-12}$ meters (m). 1 millimeter (mm) is equal to $10^{-3}$ meters (m).

Step 2: Converting Picometers to Meters

First, convert the given distance from picometers to meters: \[ 115 \, \text{pm} = 115 \times 10^{-12} \, \text{m} \]

Step 3: Converting Meters to Millimeters

Next, convert the distance from meters to millimeters: \[ 115 \times 10^{-12} \, \text{m} = 115 \times 10^{-12} \times 10^{3} \, \text{mm} \] \[ 115 \times 10^{-12} \times 10^{3} = 115 \times 10^{-9} \, \text{mm} \] \[ 115 \times 10^{-9} = 1.15 \times 10^{-7} \, \text{mm} \]

Final Answer

$\boxed{1.15 \times 10^{-7} \, \text{mm}}$

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