Questions: Solve the following linear equation. Identify the equation as an identity, contradiction, or conditional equation. 3(y+1)-6(y-3)=9 y+21-12 y Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is . (Type an integer or a simplified fraction.) B. The solution is all real numbers. C. The solution is the empty set. State whether the equation is an identity, contradiction, or conditional equation. Identity Contradiction Conditional equation

Solve the following linear equation. Identify the equation as an identity, contradiction, or conditional equation.
3(y+1)-6(y-3)=9 y+21-12 y

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. The solution set is   . (Type an integer or a simplified fraction.)
B. The solution is all real numbers.
C. The solution is the empty set.

State whether the equation is an identity, contradiction, or conditional equation.
Identity
Contradiction
Conditional equation
Transcript text: Solve the following linear equation. Identify the equation as an identity, contradiction, or conditional equation. \[ 3(y+1)-6(y-3)=9 y+21-12 y \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The solution set is \{ $\square$ \}. (Type an integer or a simplified fraction.) B. The solution is all real numbers. C. The solution is the empty set. State whether the equation is an identity, contradiction, or conditional equation. Identity Contradiction Conditional equation
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Solution

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Solution Steps

To solve the given linear equation, we will first simplify both sides of the equation by distributing and combining like terms. Then, we will attempt to isolate the variable \( y \) to determine if there is a specific solution, if the equation holds for all values of \( y \), or if there is no solution. Based on the result, we will classify the equation as an identity, contradiction, or conditional equation.

Step 1: Expand the Equation

First, we need to expand the given linear equation:

\[ 3(y+1) - 6(y-3) = 9y + 21 - 12y \]

Expanding each term:

  • \(3(y+1) = 3y + 3\)
  • \(-6(y-3) = -6y + 18\)

Substituting these into the equation, we have:

\[ 3y + 3 - 6y + 18 = 9y + 21 - 12y \]

Step 2: Simplify Both Sides

Now, let's simplify both sides of the equation:

Left side:

\[ 3y + 3 - 6y + 18 = -3y + 21 \]

Right side:

\[ 9y + 21 - 12y = -3y + 21 \]

Step 3: Compare Both Sides

After simplification, the equation becomes:

\[ -3y + 21 = -3y + 21 \]

Both sides of the equation are identical, which means the equation holds true for all values of \(y\).

Step 4: Determine the Type of Equation

Since the equation is true for all values of \(y\), it is an identity.

Final Answer

The solution is all real numbers, and the equation is an identity.

\[ \boxed{\text{B. The solution is all real numbers.}} \]

\[ \boxed{\text{Identity}} \]

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