To solve the inequality \(2x + 5 \leq 3x - 10\), we need to isolate the variable \(x\) on one side. We can do this by first subtracting \(2x\) from both sides, and then adding 10 to both sides to solve for \(x\).
Step 1: Rearranging the Inequality
We start with the inequality:
\[
2x + 5 \leq 3x - 10
\]
To isolate \(x\), we first subtract \(2x\) from both sides:
\[
5 \leq x - 10
\]
Step 2: Solving for \(x\)
Next, we add 10 to both sides:
\[
15 \leq x
\]
This can be rewritten as:
\[
x \geq 15
\]
Step 3: Expressing the Solution
The solution indicates that \(x\) can take any value greater than or equal to 15. In interval notation, this is expressed as:
\[
[15, \infty)
\]
Final Answer
Thus, the solution to the inequality is:
\[
\boxed{x \geq 15}
\]