Oxygen (O): 3 (1 from \(\mathrm{CO}_{2}\) and 2 from \(\mathrm{H}_{2}\mathrm{O}\))
Step 3: Balance the Carbon Atoms
To balance the carbon atoms, we need 5 \(\mathrm{CO}_{2}\) molecules on the right side:
\[
\mathrm{C}_{5} \mathrm{H}_{8} + \mathrm{O}_{2} \rightarrow 5 \mathrm{CO}_{2} + \mathrm{H}_{2} \mathrm{O}
\]
Step 4: Balance the Hydrogen Atoms
To balance the hydrogen atoms, we need 4 \(\mathrm{H}_{2}\mathrm{O}\) molecules on the right side:
\[
\mathrm{C}_{5} \mathrm{H}_{8} + \mathrm{O}_{2} \rightarrow 5 \mathrm{CO}_{2} + 4 \mathrm{H}_{2}\mathrm{O}
\]
Step 5: Balance the Oxygen Atoms
Now, we count the oxygen atoms on the right side:
From \(\mathrm{CO}_{2}\): \(5 \times 2 = 10\)
From \(\mathrm{H}_{2}\mathrm{O}\): \(4 \times 1 = 4\)
Total oxygen atoms needed: \(10 + 4 = 14\)
To balance the oxygen atoms, we need 7 \(\mathrm{O}_{2}\) molecules on the left side:
\[
\mathrm{C}_{5} \mathrm{H}_{8} + 7 \mathrm{O}_{2} \rightarrow 5 \mathrm{CO}_{2} + 4 \mathrm{H}_{2}\mathrm{O}
\]
Final Answer
The coefficients that correctly balance the equation are:
\[
\boxed{1, 7, 5, 4}
\]