To solve the given expression \(3t^2 + 5t + 6\) for \(t = -3\), we need to substitute \(-3\) for \(t\) in the expression and then evaluate it.
We start with the expression \( 3t^2 + 5t + 6 \). To find its value when \( t = -3 \), we substitute \(-3\) for \( t \):
\[ 3(-3)^2 + 5(-3) + 6 \]
First, calculate \( (-3)^2 \):
\[ (-3)^2 = 9 \]
Next, multiply by 3:
\[ 3 \times 9 = 27 \]
Then, calculate \( 5(-3) \):
\[ 5 \times (-3) = -15 \]
Finally, add all the terms together:
\[ 27 + (-15) + 6 = 27 - 15 + 6 = 18 \]
The value of the expression \( 3t^2 + 5t + 6 \) when \( t = -3 \) is \(\boxed{18}\).
The answer is (d) 18.
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