Questions: Approximate the solutions to the following equation on the interval [0,2 π). Round your answer to four decimal places.
sin θ=-0.57
Select the correct choice and fill in any answer boxes in your choice.
A. θ ≈
(Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.)
B. There is no solution.
Transcript text: Approximate the solutions to the following equation on the interval $[0,2 \pi)$. Round your answer to four decimal places.
\[
\boldsymbol{\operatorname { s i n }} \theta=-0.57
\]
Select the correct choice and fill in any answer boxes in your choice.
A. $\theta \approx$ $\square$
(Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.)
B. There is no solution.
Solution
Solution Steps
To approximate the solutions to the equation sinθ=−0.57 on the interval [0,2π), we need to find the angles θ for which the sine value is −0.57. Since the sine function is periodic and symmetric, there will be two solutions within one period [0,2π). We can use the inverse sine function to find the principal value and then determine the second solution using the properties of the sine function.
Step 1: Finding the Principal Value
To solve the equation sinθ=−0.57, we first find the principal value using the inverse sine function. The principal value is given by:
θ1=arcsin(−0.57)≈5.6767
Step 2: Finding the Second Solution
Since the sine function is negative in the third and fourth quadrants, we can find the second solution using the property of the sine function:
θ2=π−θ1≈3.7481
Step 3: Adjusting the Principal Value
The principal value θ1 is already in the interval [0,2π). Therefore, we do not need to adjust it further.
Final Answer
The solutions to the equation sinθ=−0.57 on the interval [0,2π) are:
θ≈5.6767,3.7481