Questions: Approximate the solutions to the following equation on the interval [0,2 π). Round your answer to four decimal places. sin θ=-0.57 Select the correct choice and fill in any answer boxes in your choice. A. θ ≈ (Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.) B. There is no solution.

Approximate the solutions to the following equation on the interval [0,2 π). Round your answer to four decimal places.
sin θ=-0.57
Select the correct choice and fill in any answer boxes in your choice.
A. θ ≈ 
(Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.)
B. There is no solution.
Transcript text: Approximate the solutions to the following equation on the interval $[0,2 \pi)$. Round your answer to four decimal places. \[ \boldsymbol{\operatorname { s i n }} \theta=-0.57 \] Select the correct choice and fill in any answer boxes in your choice. A. $\theta \approx$ $\square$ (Type your answer in radians. Round to four decimal places as needed. Use a comma to separate answers as needed.) B. There is no solution.
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Solution

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Solution Steps

To approximate the solutions to the equation sinθ=0.57\sin \theta = -0.57 on the interval [0,2π)[0, 2\pi), we need to find the angles θ\theta for which the sine value is 0.57-0.57. Since the sine function is periodic and symmetric, there will be two solutions within one period [0,2π)[0, 2\pi). We can use the inverse sine function to find the principal value and then determine the second solution using the properties of the sine function.

Step 1: Finding the Principal Value

To solve the equation sinθ=0.57 \sin \theta = -0.57 , we first find the principal value using the inverse sine function. The principal value is given by: θ1=arcsin(0.57)5.6767 \theta_1 = \arcsin(-0.57) \approx 5.6767

Step 2: Finding the Second Solution

Since the sine function is negative in the third and fourth quadrants, we can find the second solution using the property of the sine function: θ2=πθ13.7481 \theta_2 = \pi - \theta_1 \approx 3.7481

Step 3: Adjusting the Principal Value

The principal value θ1 \theta_1 is already in the interval [0,2π)[0, 2\pi). Therefore, we do not need to adjust it further.

Final Answer

The solutions to the equation sinθ=0.57 \sin \theta = -0.57 on the interval [0,2π)[0, 2\pi) are: θ5.6767,3.7481 \boxed{\theta \approx 5.6767, 3.7481}

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