Questions: Simplify the rational expression. Find all numbers that must be excluded from the domain of the simplified rational expression.
y^2-y-56/y^2-13y+40
Simplify the rational expression. Select the correct choice below and fill in any answer boxes in your choice.
y^2-y-56/y^2-13y+40 =
(Simplify your answer. Use positive exponents only.)
Transcript text: Simplify the rational expression. Find all numbers that must be excluded from the domain of the simplified rational expression.
\[
\frac{y^{2}-y-56}{y^{2}-13 y+40}
\]
Simplify the rational expression. Select the correct choice below and fill in any answer boxes in your choice.
\[
\frac{y^{2}-y-56}{y^{2}-13 y+40}=
\]
$\square$ (Simplify your answer. Use positive exponents only.)
Solution
Solution Steps
To simplify the given rational expression, we need to factor both the numerator and the denominator. Once factored, we can cancel out any common factors. Additionally, we need to determine the values of \( y \) that make the denominator zero, as these values must be excluded from the domain.
Step 1: Factor the Numerator and Denominator
We start with the rational expression:
\[
\frac{y^{2}-y-56}{y^{2}-13y+40}
\]
We factor the numerator \(y^{2}-y-56\) and the denominator \(y^{2}-13y+40\):
The numerator factors to \((y - 8)(y + 7)\).
The denominator factors to \((y - 8)(y - 5)\).
Step 2: Simplify the Expression
Now we can rewrite the rational expression using the factored forms:
\[
\frac{(y - 8)(y + 7)}{(y - 8)(y - 5)}
\]
We can cancel the common factor \((y - 8)\) (noting that \(y \neq 8\)):
\[
\frac{y + 7}{y - 5}
\]
Step 3: Determine Excluded Values from the Domain
To find the values that must be excluded from the domain, we set the denominator equal to zero:
\[
y - 5 = 0 \quad \Rightarrow \quad y = 5
\]
Additionally, since we canceled \((y - 8)\), we also exclude \(y = 8\). Therefore, the excluded values are:
\[
y = 5, \quad y = 8
\]
Final Answer
The simplified expression is:
\[
\frac{y + 7}{y - 5}
\]
The values that must be excluded from the domain are \(y = 5\) and \(y = 8\).