Questions: Find the product:
(8 v w-5 t)^2
Select the best answer from the choices provided.
A. 64 v^2 w^2+25 t^2
B. 64 v^2 w^2-40 t v w+25 t^2
C. 64 v^2 w^2-80 t v w+25 t^2
D. 64 v^2 w^2+80 t v w+25 t^2
Transcript text: Find the product:
\[
(8 v w-5 t)^{2}
\]
Select the best answer from the choices provided.
A. $64 v^{2} w^{2}+25 t^{2}$
B. $64 v^{2} w^{2}-40 t v w+25 t^{2}$
C. $64 v^{2} w^{2}-80 t v w+25 t^{2}$
D. $64 v^{2} w^{2}+80 t v w+25 t^{2}$
Solution
Solution Steps
To find the product of \((8vw - 5t)^2\), we need to use the formula for the square of a binomial, which is \((a - b)^2 = a^2 - 2ab + b^2\). Here, \(a = 8vw\) and \(b = 5t\). We will apply this formula to expand the given expression.
Step 1: Expand the Binomial
To expand the expression \((8vw - 5t)^2\), we apply the binomial expansion formula:
\[
(a - b)^2 = a^2 - 2ab + b^2
\]
where \(a = 8vw\) and \(b = 5t\).
Step 2: Calculate Each Term
Calculating each term:
The first term is:
\[
(8vw)^2 = 64v^2w^2
\]
The second term is:
\[
-2(8vw)(5t) = -80tvw
\]
The third term is:
\[
(5t)^2 = 25t^2
\]
Step 3: Combine the Terms
Combining all the terms, we have:
\[
(8vw - 5t)^2 = 64v^2w^2 - 80tvw + 25t^2
\]
Final Answer
Thus, the expanded form of the expression is:
\[
\boxed{64v^2w^2 - 80tvw + 25t^2}
\]