Questions: Part 1: Understanding Ionic Bonds Step 1: Identify proton/electron #; Draw the electron and valence shells. Proton: protons: 17 electrons: 17 electron: 11 Oxygen Carbon Step 2: Indicate how the elements become ionic through drawing. Step 3: Draw the end product. What force is resulting in this ionic bond?

Part 1: Understanding Ionic Bonds Step 1: Identify proton/electron #; Draw the electron and valence shells. Proton: protons: 17 electrons: 17 electron: 11 Oxygen Carbon Step 2: Indicate how the elements become ionic through drawing. Step 3: Draw the end product. What force is resulting in this ionic bond?
Transcript text: Part 1: Understanding Ionic Bonds Step 1: Identify proton/electron #; Draw the electron and valence shells. Proton: protons: 17 electrons: 17 electron: 11 Oxygen Carbon Step 2: Indicate how the elements become ionic through drawing. Step 3: Draw the end product. What force is resulting in this ionic bond?
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Solution

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Solution Steps

Step 1: Identify proton/electron #; Draw the electron and valence shells.
  • Sodium (Na) has 11 protons and 11 electrons. Its electron configuration is 2, 8, 1.
  • Chlorine (Cl) has 17 protons and 17 electrons. Its electron configuration is 2, 8, 7.
Step 2: Indicate how the elements become ionic through drawing.
  • Sodium (Na) will lose one electron to achieve a stable electron configuration (2, 8).
  • Chlorine (Cl) will gain one electron to achieve a stable electron configuration (2, 8, 8).
Step 3: Draw the end product. What force is resulting in this ionic bond?
  • After the transfer of the electron, Sodium (Na) becomes a positively charged ion (Na⁺) and Chlorine (Cl) becomes a negatively charged ion (Cl⁻).
  • The electrostatic attraction between the oppositely charged ions (Na⁺ and Cl⁻) results in the formation of an ionic bond.

Final Answer

  • The ionic bond is formed due to the electrostatic attraction between the positively charged sodium ion (Na⁺) and the negatively charged chloride ion (Cl⁻).
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