Questions: The average price of a ticket to a baseball game can be approximated by p(x)=0.03 x number of years after 1991 and p(x) is in dollars.
a) Find p(3).
b) Find p(13).
c) Find p(13)-p(3).
d) Find (p(13)-p(3))/(13-3), and interpret this result.
a) p(3)=7.03 (Simplify your answer.)
b) p(13)=16.13 (Simplify your answer.)
c) p(13)-p(3)=9.10 (Simplify your answer.)
d) (p(13)-p(3))/(13-3)=.91 (Simplify your answer.)
Which of the following is the appropriate interpretation of this result?
A. From 1994 to 2004, the average price for a ticket increased on average by this amount per year.
B. From 1994 to 2004, the price of baseball tickets increased by this amount per year.
C. This amount was the average price difference of a baseball ticket from 1994 to 2004.
D. The result tells us that the price of a baseball ticket in 2014 is this amount more than in 2004.
Transcript text: The average price of a ticket to a baseball game can be approximated by $p(x)=0.03 x$ number of years after 1991 and $p(x)$ is in dollars.
a) Find $p(3)$.
b) Find $p(13)$.
c) Find $p(13)-p(3)$.
d) Find $\frac{p(13)-p(3)}{13-3}$, and interpret this result.
a) $p(3)=7.03$ (Simplify your answer.)
b) $p(13)=16.13$ (Simplify your answer.)
c) $p(13)-p(3)=9.10$ (Simplify your answer.)
d) $\frac{p(13)-p(3)}{13-3}=.91$ (Simplify your answer.)
Which of the following is the appropriate interpretation of this result?
A. From 1994 to 2004, the average price for a ticket increased on average by this amount per year.
B. From 1994 to 2004, the price of baseball tickets increased by this amount per year.
C. This amount was the average price difference of a baseball ticket from 1994 to 2004.
D. The result tells us that the price of a baseball ticket in 2014 is this amount more than in 2004.
Solution
Solution Steps
Step 1: Calculate \( p(3) \)
Substitute \( x = 3 \) into the equation \( p(x) = 0.03x \):
\[
p(3) = 0.03 \cdot 3 = 0.09 \text{ dollars.}
\]
Step 2: Calculate \( p(13) \)
Substitute \( x = 13 \) into the equation \( p(x) = 0.03x \):
\[
p(13) = 0.03 \cdot 13 = 0.39 \text{ dollars.}
\]