We start with the equation:
\[
\frac{6}{v-6} = \frac{v}{v-6} + 3
\]
Since both sides have the same denominator \( v - 6 \), we can eliminate the denominators by multiplying through by \( v - 6 \) (assuming \( v \neq 6 \)):
\[
6 = v + 3(v - 6)
\]
Step 2: Simplify the Equation
Expanding the right-hand side gives:
\[
6 = v + 3v - 18
\]
Combining like terms results in:
\[
6 = 4v - 18
\]
Step 3: Solve for \( v \)
Next, we isolate \( v \) by adding 18 to both sides:
\[
24 = 4v
\]
Dividing both sides by 4 yields:
\[
v = 6
\]
Step 4: Check for Validity
However, substituting \( v = 6 \) back into the original equation leads to a division by zero in the denominators, which is undefined. Therefore, \( v = 6 \) is not a valid solution.
Final Answer
Since there are no valid solutions, we conclude:
\[
\boxed{\text{No solution}}
\]