Chromium(II) acetate is represented by the chemical formula Cr(CH3COO)2. This indicates that each formula unit of chromium(II) acetate contains two acetate ions, CH3COO−.
Since each mole of Cr(CH3COO)2 contains 2 moles of CH3COO−, we can calculate the total moles of acetate ions by multiplying the moles of chromium(II) acetate by 2:
Moles of acetate ions=4.05moles of Cr(CH3COO)2×2=8.10moles of CH3COO−
To find the moles of Cr(CH3COO)2 from a given number of moles of acetate ions, we divide the moles of acetate ions by 2, since each mole of Cr(CH3COO)2 contains 2 moles of acetate ions:
Moles of Cr(CH3COO)2=23.41moles of CH3COO−=1.705moles of Cr(CH3COO)2
- 8.10moles of CH3COO−
- 1.705moles of Cr(CH3COO)2