Questions: Calculate the heat required to raise the temperature of 28.6 g of sodium from 33.7°C to 73.8°C. The specific heat capacity of sodium is 1.23 J /(g · °C). 1.41 x 10^3 J 932 J 1.19 x 10^3 J 2.60 x 10^3 J

Solution Steps

We are given:

• Mass of sodium, \( m = 28.6 \, \text{g} \)
• Initial temperature, \( T_i = 33.7^\circ \text{C} \)
• Final temperature, \( T_f = 73.8^\circ \text{C} \)
• Specific heat capacity of sodium, \( c = 1.23 \, \text{J/g} \cdot {}^\circ \text{C} \)

The change in temperature, \(\Delta T\), is calculated as: \[ \Delta T = T_f - T_i = 73.8^\circ \text{C} - 33.7^\circ \text{C} = 40.1^\circ \text{C} \]

The formula to calculate the heat required is: \[ q = m \cdot c \cdot \Delta T \] Substituting the given values: \[ q = 28.6 \, \text{g} \cdot 1.23 \, \text{J/g} \cdot {}^\circ \text{C} \cdot 40.1^\circ \text{C} \]

Calculate the heat required: \[ q = 28.6 \times 1.23 \times 40.1 = 1410.1 \, \text{J} \]

Final Answer