Questions: Use the long division method to find the result when 2x^3 - 6x^2 + x + 9 is divided by x + 1. If there is a remainder, express the result in the form q(x) + r(x)/b(x).
Transcript text: Use the long division method to find the result when $2 x^{3}-6 x^{2}+x+9$ is divided by $x+1$. If there is a remainder, express the result in the form $q(x)+\frac{r(x)}{b(x)}$.
Solution
Solution Steps
Step 1: Setup
Given the dividend polynomial $P(x)$ and the divisor polynomial $D(x)$, we write them in standard form ensuring all terms are present.
$P(x) = 2x^3 - 6x^2 + x^1 + 9x^0$
$D(x) = x^1 + x^0$
Step 2: Division Step
The leading term of $P(x)$ is divided by the leading term of $D(x)$ to find the first term of the quotient $q(x)$.
Step 3: Multiply and Subtract
Multiply $D(x)$ by the term just found and subtract the result from $P(x)$ to get a new polynomial.
Step 4: Repeat
This process is repeated, treating the new polynomial as the dividend, until the degree of the remainder is less than the degree of $D(x)$.
Final Answer:
The result of the division is $q(x) = 2.0x^2 - 8.0x^1 + 9$ with no remainder.