Questions: Build a reference triangle below for θ=330° and use your labeled triangle to find sin θ and tan θ.

Build a reference triangle below for θ=330° and use your labeled triangle to find sin θ and tan θ.
Transcript text: Build a reference triangle below for $\theta=330^{\circ}$ and use your labeled triang to find $\sin \theta$ and $\tan \theta$.
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Solution

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Solution Steps

Step 1: Determine the Reference Angle

The given angle is \( \theta = 330^\circ \). To find the reference angle, subtract \( 330^\circ \) from \( 360^\circ \): \[ 360^\circ - 330^\circ = 30^\circ \] So, the reference angle is \( 30^\circ \).

Step 2: Draw the Reference Triangle

Draw a right triangle in the fourth quadrant with the reference angle \( 30^\circ \). Label the sides of the triangle based on the standard 30-60-90 triangle ratios:

  • Opposite side to \( 30^\circ \): \( 1 \)
  • Adjacent side to \( 30^\circ \): \( \sqrt{3} \)
  • Hypotenuse: \( 2 \)
Step 3: Determine the Signs of the Trigonometric Functions

Since \( 330^\circ \) is in the fourth quadrant:

  • Sine is negative.
  • Cosine is positive.
  • Tangent is negative.
Step 4: Calculate \( \sin \theta \) and \( \tan \theta \)

Using the reference triangle: \[ \sin 330^\circ = -\sin 30^\circ = -\frac{1}{2} \] \[ \tan 330^\circ = -\tan 30^\circ = -\frac{1}{\sqrt{3}} = -\frac{\sqrt{3}}{3} \]

Final Answer

\[ \sin 330^\circ = -\frac{1}{2} \] \[ \tan 330^\circ = -\frac{\sqrt{3}}{3} \]

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