To find the equation of the line that passes through two points, we can use the point-slope form of the equation of a line. The steps are as follows:
To find the slope \( m \) of the line that passes through the points \((-5, 3)\) and \((4, 6)\), we use the formula:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{6 - 3}{4 - (-5)} = \frac{3}{9} = \frac{1}{3} \]
Next, we apply the point-slope form of the equation of a line, which is given by:
\[ y - y_1 = m(x - x_1) \]
Using the point \((-5, 3)\) and the slope \( m = \frac{1}{3} \):
\[ y - 3 = \frac{1}{3}(x - (-5)) \]
Now, we rearrange the equation to the slope-intercept form \( y = mx + b \):
\[ y - 3 = \frac{1}{3}(x + 5) \]
Distributing the slope:
\[ y - 3 = \frac{1}{3}x + \frac{5}{3} \]
Adding 3 to both sides:
\[ y = \frac{1}{3}x + \frac{5}{3} + 3 \]
Converting 3 to a fraction with a common denominator:
\[ 3 = \frac{9}{3} \]
Thus, we have:
\[ y = \frac{1}{3}x + \frac{5}{3} + \frac{9}{3} = \frac{1}{3}x + \frac{14}{3} \]
The equation of the line is
\[ \boxed{y = \frac{1}{3}x + \frac{14}{3}} \]
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