Questions: Consider the structure shown below: 1. One thing is incorrect about this Lewis structure. What is it? (5 pts) 2. Draw the correct Lewis structure for this compound (5 pts)

Consider the structure shown below: 1. One thing is incorrect about this Lewis structure. What is it? (5 pts) 2. Draw the correct Lewis structure for this compound (5 pts)
Transcript text: Consider the structure shown below: 1. One thing is incorrect about this Lewis structure. What is it? (5 pts) 2. Draw the correct Lewis structure for this compound (5 pts)
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Solution

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Solution Steps

Step 1: Identifying the incorrect feature

The given structure shows a carbon atom bonded to two tert-butyl groups and two hydrogen atoms. Each tert-butyl group has four carbon atoms. Three methyl groups (CH3) are attached to a central carbon atom. The central carbon of each tert-butyl group is bonded to the carbon atom with two hydrogens. The central carbon with the two hydrogens appears to show 10 valence electrons. Carbon can only have 8 valence electrons (octet rule). This is the incorrect feature.

Step 2: Drawing the correct Lewis structure

The central carbon atom with two hydrogen atoms forms a double bond with one of the tert-butyl groups' central carbons to avoid exceeding the octet rule. This forms 2-methylprop-1-ene, an alkene. The correct Lewis structure has a double bond between one carbon and another instead of each having a single bond with two other carbons. The other tert-butyl group is correctly bonded to the same central carbon through a single bond.

Final Answer

  1. The central carbon atom appears to have 10 valence electrons. Carbon can only have a maximum of 8 valence electrons.

  2. Correct Lewis structure:

    CH3 | H3C-C=CH2 | CH3 | CH3-C-CH3 | CH3

It may be easier to visualize by showing each carbon individually:

 CH3       H
  |       |

H3C-C=C-C-CH3 | | CH3 CH3 | CH3

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