Questions: Volume Surface Question 13, 8.4.21 HW Score: 40.52% Points: 0 of 1 Determine the volume of the shaded region. Use the π button on your calculator. The volume of the shaded region is (Simplify your answer. Type an integer or a decimal rounded to the nearest hundredth as needed.)

Volume  Surface
Question 13, 8.4.21
HW Score: 40.52%
Points: 0 of 1

Determine the volume of the shaded region. Use the π button on your calculator.

The volume of the shaded region is  
(Simplify your answer. Type an integer or a decimal rounded to the nearest hundredth as needed.)
Transcript text: Volume \& Surface Question 13, 8.4.21 HW Score: $40.52 \%$ Points: 0 of 1 Determine the volume of the shaded region. Use the $\pi$ button on your calculator. The volume of the shaded region is $\square$ $\square$ (Simplify your answer. Type an integer or a decimal rounded to the nearest hundredth as needed.)
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Solution

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Solution Steps

Step 1: Calculate the Volume of the Cylinder

The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] where \( r \) is the radius and \( h \) is the height.

Given:

  • Diameter of the cylinder = 6 cm, so radius \( r = \frac{6}{2} = 3 \) cm
  • Height \( h = 17.4 \) cm

\[ V_{\text{cylinder}} = \pi (3)^2 (17.4) = \pi (9) (17.4) = 156.6\pi \]

Step 2: Calculate the Volume of One Sphere

The volume \( V \) of a sphere is given by the formula: \[ V = \frac{4}{3} \pi r^3 \] where \( r \) is the radius.

Given:

  • Diameter of the sphere = 5.7 cm, so radius \( r = \frac{5.7}{2} = 2.85 \) cm

\[ V_{\text{sphere}} = \frac{4}{3} \pi (2.85)^3 \approx \frac{4}{3} \pi (23.144625) \approx 30.86\pi \]

Step 3: Calculate the Total Volume of the Spheres

There are 3 spheres in the cylinder.

\[ V_{\text{total spheres}} = 3 \times 30.86\pi = 92.58\pi \]

Step 4: Calculate the Volume of the Shaded Region

The volume of the shaded region is the volume of the cylinder minus the total volume of the spheres.

\[ V_{\text{shaded}} = V_{\text{cylinder}} - V_{\text{total spheres}} = 156.6\pi - 92.58\pi = 64.02\pi \]

Final Answer

\[ V_{\text{shaded}} \approx 64.02\pi \approx 201.06 \, \text{cm}^3 \]

The volume of the shaded region is approximately \( 201.06 \, \text{cm}^3 \).

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