Questions: Measurement and Matter Setting up the math for a one-step quantitative problem Super fine 40-gauge copper wire has a diameter of only 0.080 mm and weighs only 44.5 g / km. Suppose a spool of 40-gauge wire weighs 830 g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. length of wire =

Measurement and Matter Setting up the math for a one-step quantitative problem Super fine 40-gauge copper wire has a diameter of only 0.080 mm and weighs only 44.5 g / km. Suppose a spool of 40-gauge wire weighs 830 g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. length of wire =
Transcript text: Measuremaent and Matter Setting up the math for a one-step quantitative probiem Super fine 40 -gauge copper wire has a diameter of only 0.080 mm and weighs only $44.5 \mathrm{~g} / \mathrm{km}$. Suppose a spool of 40 -gauge wire weighs 830 . g less after some wire is pulled off to wind a magnet. How could you calculate how much wire was used? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols. length of wire $=$
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the weight difference (Δw)

The weight difference (Δw) is given as 830 grams.

Step 2: Determine the weight per unit length (w_l)

The weight per unit length (w_l) is given as 44.5 grams per unit length.

Step 3: Convert the weight per unit length into a consistent unit if necessary

In this problem, it is assumed that the units are consistent and conversion is not required.

Step 4: Calculate the length of wire used

Using the formula: \[\text{length of wire used} = \frac{\Delta w}{w_l}\] Substituting the given values: \[\text{length of wire used} = \frac{830}{44.5}\] The calculated length of wire used is 18.65 units.

Final Answer

The length of wire used is 18.65 units, rounded to 2 decimal places.

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
Which of the following transactions affect Owner's Equity? a. Payment on account b. Equipment purchase on account c. Customer payment on account d. A withdrawal
failedAnswered
Estimate the limit numerically or state that the limit does not exist. lim x->0 (8^x-1)/x Start by calculating the values of the function for the inputs listed in this table. f(x) ------------- 0.01 0.001 0.0001 -0.0001 -0.001 -0.01 Based on the values in this table, it appears lim x->0 (8^x-1)/x= Give your answer accurate to 3 decimal places
failedAnswered
Let f=(2,-9),(-9,-9),(-2,2). Find (a) f(-9) and (b) f(2).
failedAnswered
Find the horizontal and vertical asymptotes. f(x)=(7x^2+36)/(x^2-36)
failedAnswered
Calorimetry Thermodynamics A 5.00 kg block of metal with c=650 J /(kg*C) at 80.0°C comes in contact with a 1.25 kg glass block at 20.0°C. They come to equilibrium at 63.9°C. What is the specific heat of the glass? (Unit =J /(kg*C))