Questions: Use Fleury's algorithm to determine an Euler path Choose the correct answer below. A. N, O, Q, P, M, N, L, M, S, P, Q, S, R, Q B. MNPMSPQSRONLM C. L,M,N,L,R,S,M,P,S,Q,P,N,O,Q,R D. L, M, S, R, L, N, M, P, S, R, Q, O, N, P, Q, R

Use Fleury's algorithm to determine an Euler path

Choose the correct answer below.
A. N, O, Q, P, M, N, L, M, S, P, Q, S, R, Q
B. MNPMSPQSRONLM
C. L,M,N,L,R,S,M,P,S,Q,P,N,O,Q,R
D. L, M, S, R, L, N, M, P, S, R, Q, O, N, P, Q, R

Transcript text: Use Fleury's algorithm to determine an Euler path Choose the correct answer below. A. $N, O, Q, P, M, N, L, M, S, P, Q, S, R, Q$ B. MNPMSPQSRONLM C. L,M,N,L,R,S,M,P,S,Q,P,N,O,Q,R D. $L, M, S, R, L, N, M, P, S, R, Q, O, N, P, Q, R$

Solution

Solution Steps

Step 1: Check if an Euler path or circuit exists

An Euler path exists if a graph has exactly two vertices with odd degrees. An Euler circuit exists if all vertices have even degrees. In this graph, vertices L, M, R, and S have degree 3 (odd). Since there are more than two vertices with odd degrees, an Euler _path_ doesn't exist and neither does an Euler circuit.

Step 2: Analyze the provided options

Since no Euler path exists, none of the options can be a valid Euler path.

Step 3: Identify the most likely intended answer

Option C starts and ends at vertices with odd degrees (L and R), which is a requirement for an Euler path. While not a true Euler path, option C is the closest to being valid considering the given incorrect premise.