To find the magnitude of the vector \(\vec{v} = (1, 2, 2)\), we use the formula for the Euclidean norm:
\[ \|\vec{v}\| = \sqrt{v_1^2 + v_2^2 + v_3^2} \]
Substituting the components of \(\vec{v}\):
\[ \|\vec{v}\| = \sqrt{1^2 + 2^2 + 2^2} = \sqrt{1 + 4 + 4} = \sqrt{9} = 3 \]
To find the normalized vector \(\hat{v}\), we divide each component of \(\vec{v}\) by its magnitude \(\|\vec{v}\|\):
\[ \hat{v} = \frac{\vec{v}}{\|\vec{v}\|} = \left( \frac{1}{3}, \frac{2}{3}, \frac{2}{3} \right) \]
The magnitude of \(\vec{v}\) is:
\[ \boxed{\|\vec{v}\| = 3} \]
The normalized vector \(\hat{v}\) is:
\[ \boxed{\hat{v} = \left( \frac{1}{3}, \frac{2}{3}, \frac{2}{3} \right)} \]
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