Questions: 4-7 Skills Practice Functions and Graphs Copy and complete each function table. 1. y=x-1 x, x-1, y 1, , 2, , 3, , 4, , 4. y=-4 x x, -4 x, y -1, , 0, , 1, , 2, , 2. y=x+7 x, x+7 1, 2, 3, 4, 5. y=3 x+1 x, 3 x+1 -1, 0, 1, 2,

4-7 Skills Practice Functions and Graphs
Copy and complete each function table.
1. y=x-1
x, x-1, y
1, , 
2, , 
3, , 
4, , 

4. y=-4 x
x, -4 x, y
-1, , 
0, , 
1, , 
2, , 

2. y=x+7
x, x+7
1, 
2, 
3, 
4, 

5. y=3 x+1
x, 3 x+1
-1, 
0, 
1, 
2,
Transcript text: 4-7 Skills Practice Functions and Graphs Copy and complete each function table. 1. $y=x-1$ \begin{tabular}{|c|c|c|} \hline$x$ & $x-1$ & $y$ \\ \hline 1 & & \\ 2 & & \\ 3 & & \\ 4 & & \\ \hline \end{tabular} 4. $y=-4 x$ \begin{tabular}{|r|l|r|} \hline \multicolumn{1}{|c|}{$x$} & $-4 x$ & $y$ \\ \hline-1 & & \\ 0 & & \\ 1 & & \\ 2 & & \\ \hline \end{tabular} 2. $y=x+7$ \begin{tabular}{|c|c|} \hline$x$ & $x+7$ \\ \hline 1 & \\ 2 & \\ 3 & \\ 4 & \\ \hline \end{tabular} 5. $y=3 x+1$ \begin{tabular}{|r|l|} \hline$x$ & $3 x+1$ \\ \hline-1 & \\ 0 & \\ 1 & \\ 2 & \\ \hline \end{tabular}
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Solution

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Solution Steps

To complete each function table, substitute the given values of \( x \) into the function equations to calculate the corresponding \( y \) values. This involves simple arithmetic operations for each function.

Step 1: Function \( y = x - 1 \)

To complete the function table for \( y = x - 1 \), we substitute the values of \( x \):

  • For \( x = 1 \): \( y = 1 - 1 = 0 \)
  • For \( x = 2 \): \( y = 2 - 1 = 1 \)
  • For \( x = 3 \): \( y = 3 - 1 = 2 \)
  • For \( x = 4 \): \( y = 4 - 1 = 3 \)

Thus, the completed table is: \[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 0 \\ 2 & 1 \\ 3 & 2 \\ 4 & 3 \\ \hline \end{array} \]

Step 2: Function \( y = -4x \)

Next, we complete the function table for \( y = -4x \):

  • For \( x = -1 \): \( y = -4 \times (-1) = 4 \)
  • For \( x = 0 \): \( y = -4 \times 0 = 0 \)
  • For \( x = 1 \): \( y = -4 \times 1 = -4 \)
  • For \( x = 2 \): \( y = -4 \times 2 = -8 \)

Thus, the completed table is: \[ \begin{array}{|r|r|} \hline x & y \\ \hline -1 & 4 \\ 0 & 0 \\ 1 & -4 \\ 2 & -8 \\ \hline \end{array} \]

Step 3: Function \( y = x + 7 \)

Finally, we complete the function table for \( y = x + 7 \):

  • For \( x = 1 \): \( y = 1 + 7 = 8 \)
  • For \( x = 2 \): \( y = 2 + 7 = 9 \)
  • For \( x = 3 \): \( y = 3 + 7 = 10 \)
  • For \( x = 4 \): \( y = 4 + 7 = 11 \)

Thus, the completed table is: \[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 8 \\ 2 & 9 \\ 3 & 10 \\ 4 & 11 \\ \hline \end{array} \]

Final Answer

The completed function tables are:

  1. For \( y = x - 1 \): \[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 0 \\ 2 & 1 \\ 3 & 2 \\ 4 & 3 \\ \hline \end{array} \]
  2. For \( y = -4x \): \[ \begin{array}{|r|r|} \hline x & y \\ \hline -1 & 4 \\ 0 & 0 \\ 1 & -4 \\ 2 & -8 \\ \hline \end{array} \]
  3. For \( y = x + 7 \): \[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 8 \\ 2 & 9 \\ 3 & 10 \\ 4 & 11 \\ \hline \end{array} \]

Thus, the final answer is boxed as follows: \[ \boxed{\text{Completed tables as shown above}} \]

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