First, simplify the expression 23×222^3 \times 2^223×22.
23×22=23+2=25 2^3 \times 2^2 = 2^{3+2} = 2^5 23×22=23+2=25
Now, compare 252^525 with 262^626.
We have:
Since 32<6432 < 6432<64, we have:
25<26 2^5 < 2^6 25<26
The expression 23×222^3 \times 2^223×22 is less than 262^626. Therefore, the correct order is:
23×22 < 26 2^3 \times 2^2 \, \boxed{<} \, 2^6 23×22<26
Oops, Image-based questions are not yet availableUse Solvely.ai for full features.
Failed. You've reached the daily limit for free usage.Please come back tomorrow or visit Solvely.ai for additional homework help.