First, simplify the expression \(2^3 \times 2^2\).
\[ 2^3 \times 2^2 = 2^{3+2} = 2^5 \]
Now, compare \(2^5\) with \(2^6\).
We have:
Since \(32 < 64\), we have:
\[ 2^5 < 2^6 \]
The expression \(2^3 \times 2^2\) is less than \(2^6\). Therefore, the correct order is:
\[ 2^3 \times 2^2 \, \boxed{<} \, 2^6 \]
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