Questions: A binomial experiment with probability of success p=0.6 and n=6 trials is conducted. What is the probability that the experiment results in exactly 2 successes?
Do not round your intermediate computations, and round your answer to three decimal places. (If necessary, consult a list of formulas.)
Transcript text: A binomial experiment with probability of success $p=0.6$ and $n=6$ trials is conducted. What is the probability that the experiment results in exactly 2 successes?
Do not round your intermedlate computations, and round your answer to three decimal places. (If necessary, consult a list of formulas.)
Solution
Solution Steps
Step 1: Calculate the binomial coefficient
The binomial coefficient \(\binom{n}{k}\) is calculated as \(\frac{n!}{k!(n-k)!}\),
which is \(\frac{720!}{2!(24!}\) = 15.
Step 2: Calculate the probability of k successes and n-k failures
The probability of exactly 2 successes (\(p^k\)) is calculated as \(0.6^{2} = 0.36\),
and the probability of 4 failures (\((1-p)^{n-k}\)) is \((1-0.6)^{4} = 0.0256\).
Step 3: Calculate the final probability
The final probability \(P(X = k)\) is calculated as the product of the binomial coefficient,
the probability of 2 successes, and the probability of 4 failures,
which is 15 * 0.36 * 0.0256 = 0.138.
Final Answer:
The probability of achieving exactly 2 successes in 6 trials of a binomial experiment,
where the probability of success in each trial is 0.6, is approximately 0.138.