Questions: Find f ∘ g and g ∘ f. f(x) = sqrt(x+1), g(x) = x^2 (a) f ∘ g (b) g ∘ f

Find f ∘ g and g ∘ f.
f(x) = sqrt(x+1), g(x) = x^2
(a) f ∘ g
(b) g ∘ f
Transcript text: Find $f \circ g$ and $g \circ f$. \[ f(x)=\sqrt{x+1}, \quad g(x)=x^{2} \] (a) $f \circ g$ (b) $g \circ f$
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Solution

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Solution Steps

To find the compositions of the functions \( f \) and \( g \), we need to substitute one function into the other. Specifically: (a) For \( f \circ g \), substitute \( g(x) \) into \( f(x) \). (b) For \( g \circ f \), substitute \( f(x) \) into \( g(x) \).

Step 1: Find \( f \circ g \)

To find \( f \circ g \), we substitute \( g(x) = x^2 \) into \( f(x) = \sqrt{x + 1} \): \[ f \circ g = f(g(x)) = f(x^2) = \sqrt{x^2 + 1} \]

Step 2: Find \( g \circ f \)

Next, we find \( g \circ f \) by substituting \( f(x) = \sqrt{x + 1} \) into \( g(x) = x^2 \): \[ g \circ f = g(f(x)) = g(\sqrt{x + 1}) = (\sqrt{x + 1})^2 = x + 1 \]

Final Answer

The results of the compositions are:

  • \( f \circ g = \sqrt{x^2 + 1} \)
  • \( g \circ f = x + 1 \)

Thus, the final answers are: \[ \boxed{f \circ g = \sqrt{x^2 + 1}} \] \[ \boxed{g \circ f = x + 1} \]

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