To clear the parentheses, distribute \(\frac{7}{5}\) across the terms inside the parentheses:
\[ \frac{7}{5}(3x + 4) = \frac{7}{5} \cdot 3x + \frac{7}{5} \cdot 4 \]
This simplifies to:
\[ \frac{21}{5}x + \frac{28}{5} \]
Set the distributed expression equal to \(x\):
\[ \frac{21}{5}x + \frac{28}{5} = x \]
Multiply every term by 5 to eliminate the fractions:
\[ 5 \left(\frac{21}{5}x + \frac{28}{5}\right) = 5x \]
\[ 21x + 28 = 5x \]
Subtract \(5x\) from both sides to isolate terms involving \(x\):
\[ 21x - 5x + 28 = 0 \]
\[ 16x + 28 = 0 \]
Subtract 28 from both sides:
\[ 16x = -28 \]
Divide both sides by 16 to solve for \(x\):
\[ x = \frac{-28}{16} \]
Simplify the fraction:
\[ x = -\frac{7}{4} \]
\[ \boxed{x = -\frac{7}{4}} \]
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