Questions: Solve 2x-1+4 ≤ 5 and write the solution in interval notation. (If there is no solution, enter your answer as ∅.)
Transcript text: Solve $|2 x-1|+4 \leq 5$ and write the solution in interval notation.
(If there is no solution, enter your answer as $\varnothing$.)
Solution
Solution Steps
To solve the absolute value inequality \( |2x - 1| + 4 \leq 5 \), we first isolate the absolute value expression by subtracting 4 from both sides, resulting in \( |2x - 1| \leq 1 \). This inequality can be split into two separate inequalities: \( 2x - 1 \leq 1 \) and \( 2x - 1 \geq -1 \). Solving these inequalities will give us the range of values for \( x \). Finally, we express the solution in interval notation.
Step 1: Understand the Problem
We are given the inequality \( |2x - 1| + 4 \leq 5 \). Our task is to solve this inequality and express the solution in interval notation.
Step 2: Isolate the Absolute Value
First, we need to isolate the absolute value expression. We do this by subtracting 4 from both sides of the inequality:
\[
|2x - 1| + 4 - 4 \leq 5 - 4
\]
This simplifies to:
\[
|2x - 1| \leq 1
\]
Step 3: Solve the Absolute Value Inequality
The inequality \( |2x - 1| \leq 1 \) can be split into two separate inequalities:
\( 2x - 1 \leq 1 \)
\( 2x - 1 \geq -1 \)
Solving the First Inequality
\[
2x - 1 \leq 1
\]
Add 1 to both sides:
\[
2x \leq 2
\]
Divide both sides by 2:
\[
x \leq 1
\]
Solving the Second Inequality
\[
2x - 1 \geq -1
\]
Add 1 to both sides:
\[
2x \geq 0
\]
Divide both sides by 2:
\[
x \geq 0
\]
Step 4: Combine the Solutions
The solution to the inequality \( |2x - 1| \leq 1 \) is the intersection of the solutions to the two inequalities:
\[
0 \leq x \leq 1
\]
Step 5: Write the Solution in Interval Notation
The solution in interval notation is:
\[
[0, 1]
\]
Final Answer
The solution to the inequality \( |2x - 1| + 4 \leq 5 \) is \(\boxed{[0, 1]}\).