Questions: The graph of x^2 + (y-2)^2 = 4 has center with coordinates

Transcript text: The graph of $x^{2}+(y-2)^{2}=4$ has center with coordinates

Solution

Solution Steps

Step 1: Identify the values of $h$ and $k$

The given equation of the circle is $(x-0)^2 + (y-2)^2 = 2^2$. From this equation, we can directly identify the values of $h$ and $k$, which represent the x and y coordinates of the center of the circle, respectively.

Step 2: Determine the center of the circle

By substituting the identified values of $h$ and $k$ into the coordinates of the center, we find that the center of the circle is at $(0, 2)$.

Final Answer:

The center of the circle is at $(0, 2)$, with each coordinate rounded to 2 decimal places.

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