Questions: The graph of x^2 + (y-2)^2 = 4 has center with coordinates

The graph of x^2 + (y-2)^2 = 4 has center with coordinates
Transcript text: The graph of $x^{2}+(y-2)^{2}=4$ has center with coordinates
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Solution

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Solution Steps

Step 1: Identify the values of \(h\) and \(k\)

The given equation of the circle is \((x-0)^2 + (y-2)^2 = 2^2\). From this equation, we can directly identify the values of \(h\) and \(k\), which represent the x and y coordinates of the center of the circle, respectively.

Step 2: Determine the center of the circle

By substituting the identified values of \(h\) and \(k\) into the coordinates of the center, we find that the center of the circle is at \((0, 2)\).

Final Answer:

The center of the circle is at \((0, 2)\), with each coordinate rounded to 2 decimal places.

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