Questions: Graph the system of inequalities:
x-y ≤ 1
x+2y < 4
Transcript text: Graph the system of inequalities:
\[
\begin{array}{c}
x-y \leq 1 \\
x+2 y<4
\end{array}
\]
Solution
Solution Steps
Step 1: Rewrite the inequalities in slope-intercept form.
The first inequality \(x - y \leq 1\) can be rewritten as \(y \geq x - 1\). The second inequality \(x + 2y < 4\) can be rewritten as \(2y < -x + 4\), or \(y < -\frac{1}{2}x + 2\).
Step 2: Graph the first inequality.
The line \(y = x - 1\) has a slope of 1 and a y-intercept of -1. Since the inequality is \(y \geq x - 1\), we graph the line \(y = x - 1\) as a solid line and shade the region above the line.
Step 3: Graph the second inequality.
The line \(y = -\frac{1}{2}x + 2\) has a slope of \(-\frac{1}{2}\) and a y-intercept of 2. Since the inequality is \(y < -\frac{1}{2}x + 2\), we graph the line \(y = -\frac{1}{2}x + 2\) as a dashed line and shade the region below the line.
Step 4: Find the solution region.
The solution to the system of inequalities is the region where the shaded regions from both inequalities overlap.
Final Answer
The solution is the overlapping shaded region of the two inequalities, which lies above the line \(y = x-1\) (solid line) and below the line \(y = -\frac{1}{2}x+2\) (dashed line).