Questions: The following contingency table cross-classifies medical school faculty by the characteristics gender and rank. P(R3) = 0.403 b. Find P(R3 G1). P(R3 G1) = 0.367 c. Are events G1 and R3 independent? A. No. Events G1 and R3 are only independent if P(R3) ≠ P(R3 G1). B. No. Events G1 and R3 are only independent if P(R3) = P(R3 G1). C. Yes. Events G1 and R3 are independent because P(R3) = P(R3 G1). D. Yes. Events G1 and R3 are independent because P(R3) ≠ P(R3 G1). Medical school faculty gender and rank Rank veriver Male G1 Female G2 Total --------------- Professor R1 21,340 3,446 24,786 Associate professor R2 16,299 5,278 21,577 Assistant professor R3 25,502 14,045 39,547 Instructor R4 5,521 5,027 10,548 Other R5 767 849 1,616 Total 69,429 28,645 98,074

The following contingency table cross-classifies medical school faculty by the characteristics gender and rank.

P(R3) = 0.403

b. Find P(R3  G1).

P(R3  G1) = 0.367

c. Are events G1 and R3 independent?

A. No. Events G1 and R3 are only independent if P(R3) ≠ P(R3  G1).

B. No. Events G1 and R3 are only independent if P(R3) = P(R3  G1).

C. Yes. Events G1 and R3 are independent because P(R3) = P(R3  G1).

D. Yes. Events G1 and R3 are independent because P(R3) ≠ P(R3  G1).

Medical school faculty gender and rank

Rank  veriver  Male G1  Female G2  Total
---------------
Professor R1  21,340  3,446  24,786
Associate professor R2  16,299  5,278  21,577
Assistant professor R3  25,502  14,045  39,547
Instructor R4  5,521  5,027  10,548
Other R5  767  849  1,616
Total  69,429  28,645  98,074
Transcript text: The following contingency table cross-classifies medical school faculty by the characteristics gender and rank. \[ \mathrm{P}\left(\mathrm{R}_{3}\right)=0.403 \] b. Find $P\left(R_{3} \mid G_{1}\right)$. \[ P\left(R_{3} \mid G_{1}\right)=0.367 \] c. Are events $G_{1}$ and $R_{3}$ independent? A. No. Events $G_{1}$ and $R_{3}$ are only independent if $P\left(R_{3}\right) \neq P\left(R_{3} \mid G_{1}\right)$. B. No. Events $G_{1}$ and $R_{3}$ are only independent if $P\left(R_{3}\right)=P\left(R_{3} \mid G_{1}\right)$. C. Yes. Events $G_{1}$ and $R_{3}$ are independent because $P\left(R_{3}\right)=P\left(R_{3} \mid G_{1}\right)$. D. Yes. Events $G_{1}$ and $R_{3}$ are independent because $P\left(R_{3}\right) \neq P\left(R_{3} \mid G_{1}\right)$. Medical school faculty gender and rank \begin{tabular}{|c|c|c|c|c|} \hline \multirow{8}{*}{Rank} & \multicolumn{4}{|c|}{veriver} \\ \hline & & \[ \begin{array}{c} \text { Male } \\ G_{1} \end{array} \] & Female $\mathrm{G}_{2}$ & Total \\ \hline & \[ \begin{array}{l} \text { Professor } \\ \mathbf{R}_{\mathbf{1}} \end{array} \] & 21,340 & 3,446 & 24,786 \\ \hline & Associate professor $R_{2}$ & 16,299 & 5,278 & 21,577 \\ \hline & Assistant professor $R_{3}$ & 25,502 & 14,045 & 39,547 \\ \hline & \[ \begin{array}{l} \text { Instructor } \\ \mathbf{R}_{\mathbf{4}} \end{array} \] & 5,521 & 5,027 & 10,548 \\ \hline & Other $\mathrm{R}_{5}$ & 767 & 849 & 1,616 \\ \hline & Total & 69,429 & 28,645 & 98,074 \\ \hline \end{tabular}
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Solution

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Solution Steps

Step 1: Identify the given probabilities

The problem provides the following probabilities:

  • \( \mathrm{P}\left(\mathrm{R}_{3}\right) = 0.403 \)
  • \( P\left(R_{3} \mid G_{1}\right) = 0.367 \)
Step 2: Compare the probabilities to determine independence

To determine if events \( G_{1} \) and \( R_{3} \) are independent, compare \( \mathrm{P}\left(\mathrm{R}_{3}\right) \) and \( P\left(R_{3} \mid G_{1}\right) \). If they are equal, the events are independent; otherwise, they are dependent.

Step 3: Analyze the results

Since \( \mathrm{P}\left(\mathrm{R}_{3}\right) = 0.403 \) and \( P\left(R_{3} \mid G_{1}\right) = 0.367 \), these probabilities are not equal. Therefore, events \( G_{1} \) and \( R_{3} \) are not independent. The correct statement is:

  • B. No. Events \(G_{1}\) and \(R_{3}\) are only independent if \(P\left(R_{3}\right)=P\left(R_{3} \mid G_{1}\right)\).

Final Answer

\(\boxed{P(R_{3}) = 0.403}\)
\(\boxed{P(R_{3} \mid G_{1}) = 0.367}\)
The correct answer is B.

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