Questions: The following data are the distances from the workplace (in miles) for the 5 employees of a small business 4, 4, 19, 4, 19. Assuming that these distances constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.

The following data are the distances from the workplace (in miles) for the 5 employees of a small business 4, 4, 19, 4, 19. Assuming that these distances constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places.
Transcript text: The following data are the distances from the workplace (in miles) for the 5 employees of a small business $4,4,19,4,19$ Assuming that these distances constitute an entire population, find the standard deviation of the population. Round your answer to two decimal places. $\square$
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Solution

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Solution Steps

Step 1: Calculate the Mean

To find the mean \( \mu \) of the distances, we use the formula:

\[ \mu = \frac{\sum_{i=1}^N x_i}{N} \]

Given the distances \( x_1 = 4, x_2 = 4, x_3 = 19, x_4 = 4, x_5 = 19 \), we calculate:

\[ \sum x_i = 4 + 4 + 19 + 4 + 19 = 50 \]

The number of employees \( N = 5 \). Thus, the mean is:

\[ \mu = \frac{50}{5} = 10.0 \]

Step 2: Calculate the Variance

The variance \( \sigma^2 \) is calculated using the formula:

\[ \sigma^2 = \frac{\sum (x_i - \mu)^2}{N} \]

First, we find \( (x_i - \mu)^2 \) for each distance:

  • For \( x_1 = 4 \): \( (4 - 10)^2 = 36 \)
  • For \( x_2 = 4 \): \( (4 - 10)^2 = 36 \)
  • For \( x_3 = 19 \): \( (19 - 10)^2 = 81 \)
  • For \( x_4 = 4 \): \( (4 - 10)^2 = 36 \)
  • For \( x_5 = 19 \): \( (19 - 10)^2 = 81 \)

Now, summing these values:

\[ \sum (x_i - \mu)^2 = 36 + 36 + 81 + 36 + 81 = 270 \]

Thus, the variance is:

\[ \sigma^2 = \frac{270}{5} = 54.0 \]

Step 3: Calculate the Standard Deviation

The standard deviation \( \sigma \) is the square root of the variance:

\[ \sigma = \sqrt{\sigma^2} = \sqrt{54.0} \approx 7.35 \]

Final Answer

The mean of the distances is \( \mu = 10.0 \) and the population standard deviation is \( \sigma \approx 7.35 \).

\[ \boxed{\mu = 10.0} \] \[ \boxed{\sigma \approx 7.35} \]

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