Questions: Perform the row operations on the matrix and write the resulting matrix. Replace R2 by 1/2 R1 + 1/2 R2 [ 2 0 6 -2 2 12 ] A. [ 2 0 6 0 0 9 ] B. [ 2 0 6 -1 1 6 ] C. [ 2 0 6 0 2 18 ] D. [ 2 0 6 0 1 9 ]

Perform the row operations on the matrix and write the resulting matrix.
Replace R2 by 1/2 R1 + 1/2 R2

[ 2 0  6 -2 2  12 ]

A. [ 2 0  6 0 0  9 ] B. [ 2 0  6 -1 1  6 ] C. [ 2 0  6 0 2  18 ] D. [ 2 0  6 0 1  9 ]
Transcript text: Perform the row operations on the matrix and write the resulting matrix. Replace $R_{2}$ by $\frac{1}{2} R_{1}+\frac{1}{2} R_{2}$ \[ \left[\begin{array}{rr|r} 2 & 0 & 6 \\ -2 & 2 & 12 \end{array}\right] \] $\qquad$ A. $\left[\begin{array}{ll|l}2 & 0 & 6 \\ 0 & 0 & 9\end{array}\right]$ B. $\left[\begin{array}{rr|r}2 & 0 & 6 \\ -1 & 1 & 6\end{array}\right]$ c. $\left[\begin{array}{rr|r}2 & 0 & 6 \\ 0 & 2 & 18\end{array}\right]$ D. $\left[\begin{array}{ll|l}2 & 0 & 6 \\ 0 & 1 & 9\end{array}\right]$
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Solution

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Solution Steps

To perform the specified row operation on the given matrix, we need to replace the second row \( R_2 \) with the average of the first row \( R_1 \) and the current second row \( R_2 \). This involves taking half of each element in \( R_1 \) and adding it to half of the corresponding element in \( R_2 \).

Step 1: Define the Original Matrix

The original matrix is given as: \[ \begin{bmatrix} 2 & 0 & 6 \\ -2 & 2 & 12 \end{bmatrix} \]

Step 2: Perform the Row Operation

We need to replace \( R_2 \) with \( \frac{1}{2} R_1 + \frac{1}{2} R_2 \). This can be calculated as follows: \[ R_2 = \frac{1}{2} \begin{bmatrix} 2 & 0 & 6 \end{bmatrix} + \frac{1}{2} \begin{bmatrix} -2 & 2 & 12 \end{bmatrix} \] Calculating each element:

  • First element: \( \frac{1}{2}(2) + \frac{1}{2}(-2) = 1 - 1 = 0 \)
  • Second element: \( \frac{1}{2}(0) + \frac{1}{2}(2) = 0 + 1 = 1 \)
  • Third element: \( \frac{1}{2}(6) + \frac{1}{2}(12) = 3 + 6 = 9 \)

Thus, the new \( R_2 \) becomes: \[ R_2 = \begin{bmatrix} 0 & 1 & 9 \end{bmatrix} \]

Step 3: Write the Resulting Matrix

The resulting matrix after the row operation is: \[ \begin{bmatrix} 2 & 0 & 6 \\ 0 & 1 & 9 \end{bmatrix} \]

Final Answer

The resulting matrix is: \[ \boxed{ \begin{bmatrix} 2 & 0 & 6 \\ 0 & 1 & 9 \end{bmatrix} } \]

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