The given currents in the parallel circuit are:
To find the total current \( I_T \), sum the individual currents: \[ I_T = \frac{3}{4} + \frac{1}{8} + \frac{1}{16} \]
The common denominator for 4, 8, and 16 is 16. Convert each fraction: \[ \frac{3}{4} = \frac{3 \times 4}{4 \times 4} = \frac{12}{16} \] \[ \frac{1}{8} = \frac{1 \times 2}{8 \times 2} = \frac{2}{16} \] \[ \frac{1}{16} = \frac{1}{16} \]
Add the fractions: \[ I_T = \frac{12}{16} + \frac{2}{16} + \frac{1}{16} = \frac{15}{16} \]
The total current in the parallel circuit is \( \frac{15}{16} \) A.
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