Questions: To prepare for a lab experiment, Ted is making a solution that uses two types of concentrations of HCl (hydrochloric acid): 80 mL of 50% HCl solution, and 120 mL of 20% HCl solution. What is the HCl concentration of the mixed solution? a.) 32% b.) 91% c.) 38% d.) 9%

To prepare for a lab experiment, Ted is making a solution that uses two types of concentrations of HCl (hydrochloric acid): 80 mL of 50% HCl solution, and 120 mL of 20% HCl solution.

What is the HCl concentration of the mixed solution?
a.) 32%
b.) 91%
c.) 38%
d.) 9%
Transcript text: To prepare for a lab experiment, Ted is making a solution that uses two types of concentrations of HCl (hydrochloric acid): 80 mL of $50 \%$ HCl solution, and 120 mL of $20 \% \mathrm{HCl}$ solution. What is the HCl concentration of the mixed solution? a.) $32 \%$ b.) $91 \%$ c.) $38 \%$ d.) $9 \%$
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Solution

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Solution Steps

Step 1: Calculate the Amount of HCl in Each Solution
  • For the 80 mL of \(50\%\) HCl solution: \[ \text{Amount of HCl} = 80 \, \text{mL} \times 0.50 = 40 \, \text{mL} \]
  • For the 120 mL of \(20\%\) HCl solution: \[ \text{Amount of HCl} = 120 \, \text{mL} \times 0.20 = 24 \, \text{mL} \]
Step 2: Calculate the Total Amount of HCl
  • Add the amounts of HCl from both solutions: \[ \text{Total HCl} = 40 \, \text{mL} + 24 \, \text{mL} = 64 \, \text{mL} \]
Step 3: Calculate the Total Volume of the Mixed Solution
  • Add the volumes of both solutions: \[ \text{Total Volume} = 80 \, \text{mL} + 120 \, \text{mL} = 200 \, \text{mL} \]
Step 4: Calculate the Concentration of the Mixed Solution
  • Use the formula for concentration: \[ \text{Concentration} = \left( \frac{\text{Total HCl}}{\text{Total Volume}} \right) \times 100\% \] \[ \text{Concentration} = \left( \frac{64 \, \text{mL}}{200 \, \text{mL}} \right) \times 100\% = 32\% \]

Final Answer

\(\boxed{32\%}\)

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