Let the three consecutive integers be: \[ x, \quad x + 1, \quad x + 2 \]
The sum of the three consecutive integers is 42: \[ x + (x + 1) + (x + 2) = 42 \]
Combine like terms: \[ 3x + 3 = 42 \]
Subtract 3 from both sides: \[ 3x = 39 \] Divide both sides by 3: \[ x = 13 \]
The three consecutive integers are: \[ x = 13, \quad x + 1 = 14, \quad x + 2 = 15 \]
The three consecutive integers are: \[ \boxed{13, \ 14, \ 15} \]
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