Questions: Consider the following minimum problem:
Minimize: C=3x1+2x2
Subject to the constraints:
- 2x1+x2 ≥ 6
- x1+x2 ≥ 4
- x1 ≥ 0
- x2 ≥ 0
Write the dual problem for the above minimum problem by selecting the appropriate number for each blank box shown below (Do not solve the dual problem).
P= [Select ] y1+ [Select ] y2
[Select ] y1+ [Select] y2 ≤ 3
[Select ] y1+ [Select ] y2 ≤ 2
- y1 ≥ 0 ; y2 ≥ 0
Transcript text: Consider the following minimum problem:
Minimize: $\quad C=3 x_{1}+2 x_{2}$
Subject to the constraints:
\[
\left\{\begin{array}{l}
2 x_{1}+x_{2} \geq 6 \\
x_{1}+x_{2} \geq 4 \\
x_{1} \geq 0 \\
x_{2} \geq 0
\end{array}\right.
\]
Write the dual problem for the above minimum problem by selecting the appropriate number for each blank box shown below (Do not solve the dual problem).
$P=$ $\square$ [Select ] $y_{1}+$ [Select ] $\square$ $y_{2}$
[Select ] $\square$ $y_{1}+$ [Select] $\square$ $y_{2} \leq 3$
[Select ] $\square$ $y_{1}+$ [Select ] $\square$ $y_{2} \leq 2$
\[
y_{1} \geq 0 \quad ; \quad y_{2} \geq 0
\]
Solution
Solution Steps
To write the dual of a linear programming problem, we need to follow these steps:
Identify the primal problem's objective function and constraints.
For each constraint in the primal problem, there will be a corresponding variable in the dual problem.
The coefficients of the objective function in the primal become the right-hand side constants in the dual constraints.
The right-hand side constants of the primal constraints become the coefficients in the dual objective function.
The inequality direction is reversed in the dual problem.
Step 1: Primal Problem Formulation
The primal problem is defined as follows:
\[
\text{Minimize: } C = 3x_1 + 2x_2
\]
Subject to the constraints:
\[
\begin{align_}
2x_1 + x_2 & \geq 6 \\
x_1 + x_2 & \geq 4 \\
x_1 & \geq 0 \\
x_2 & \geq 0
\end{align_}
\]
Step 2: Dual Problem Formulation
To formulate the dual problem, we identify the coefficients and constraints from the primal problem. The dual problem is given by:
\[
P = 6y_1 + 4y_2
\]
Subject to the constraints:
\[
\begin{align_}
2y_1 + 1y_2 & \leq 3 \\
1y_1 + 1y_2 & \leq 2
\end{align_}
\]
with the non-negativity conditions:
\[
y_1 \geq 0, \quad y_2 \geq 0
\]
Final Answer
The dual problem is:
\[
\boxed{P = 6y_1 + 4y_2}
\]
with constraints:
\[
\boxed{2y_1 + y_2 \leq 3}
\]
\[
\boxed{y_1 + y_2 \leq 2}
\]
and non-negativity:
\[
\boxed{y_1 \geq 0, \quad y_2 \geq 0}
\]