Starting with the equation
\[ \frac{2}{k-1} = \frac{5}{3k-4} \]
we cross-multiply to eliminate the fractions:
\[ 2(3k - 4) = 5(k - 1) \]
Expanding both sides gives:
\[ 6k - 8 = 5k - 5 \]
Next, we rearrange the equation to isolate \(k\):
\[ 6k - 5k = -5 + 8 \]
This simplifies to:
\[ k = 3 \]
The solution to the equation is
\(\boxed{k = 3}\).
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