Questions: f(x) = -x^2 + 2 for x ≠ 2 -5 for x = 2 Find f(0)

f(x) =  -x^2 + 2 for x ≠ 2
         -5 for x = 2

Find f(0)
Transcript text: \[ f(x)=\left\{\begin{array}{lll} -x^{2}+2 & \text { for } & x \neq 2 \\ -5 & \text { for } & x=2 \end{array}\right. \] Find $f(0)$
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Solution

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Solution Steps

Step 1: Identify the value of \( x \) to evaluate

The problem asks to find \( f(0) \). Here, \( x = 0 \).

Step 2: Determine which piece of the function to use

The function \( f(x) \) is defined piecewise:

  • For \( x \neq 2 \), \( f(x) = -x^{2} + 2 \).
  • For \( x = 2 \), \( f(x) = -5 \).

Since \( x = 0 \) and \( 0 \neq 2 \), we use the first piece of the function: \( f(x) = -x^{2} + 2 \).

Step 3: Substitute \( x = 0 \) into the function

Substitute \( x = 0 \) into \( f(x) = -x^{2} + 2 \): \[ f(0) = -(0)^{2} + 2 \]

Step 4: Simplify the expression

Calculate \( (0)^{2} \): \[ (0)^{2} = 0 \] Substitute back into the equation: \[ f(0) = -0 + 2 = 2 \]

Final Answer

\(\boxed{2}\)

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