Questions: The table below shows the heights (in feet) and the number of stories of six notable buildings in a city. Complete parts a - f below.
Height, x 775 619 519 508 491 474
Stories, y 53 47 46 42 38 35
(e) Predict the value of y for x=321. Choose the correct answer below.
A. 47
B. 31
C. 51
D. not meaningful because the x value is outside the scope of the data
Transcript text: The table below shows the heights (in feet) and the number of stories of six notable buildings in a city. Complete parts a - f below.
\begin{tabular}{|l|c|c|c|c|c|c|}
\hline Height, $x$ & 775 & 619 & 519 & 508 & 491 & 474 \\
\hline Stories, $y$ & 53 & 47 & 46 & 42 & 38 & 35 \\
\hline
\end{tabular}
(e) Predict the value of y for $\mathrm{x}=321$. Choose the correct answer below.
A. 47
B. 31
C. 51
D. not meaningful because the x value is outside the scope of the data
Solution
Solution Steps
Step 1: Identify the given data
The table provides the heights (in feet) and the number of stories of six notable buildings in a city.
Heights (x): 775, 619, 519, 508, 491, 474
Stories (y): 53, 47, 46, 42, 38, 35
Step 2: Determine the relationship between x and y
To predict the value of y for x = 321, we need to determine the relationship between the height (x) and the number of stories (y). This can be done using linear regression or by observing the trend in the data.
Step 3: Calculate the linear regression equation
Using the least squares method, we calculate the linear regression equation \( y = mx + b \).
Calculate the means of x and y:
\[
\bar{x} = \frac{775 + 619 + 519 + 508 + 491 + 474}{6} = 564.33
\]
\[
\bar{y} = \frac{53 + 47 + 46 + 42 + 38 + 35}{6} = 43.5
\]
Calculate the y-intercept (b):
\[
b = \bar{y} - m\bar{x}
\]
\[
b = 43.5 - 0.072 \times 564.33 \approx 2.99
\]
The linear regression equation is:
\[
y = 0.072x + 2.99
\]
Step 4: Predict the value of y for x = 321
Substitute \( x = 321 \) into the linear regression equation:
\[
y = 0.072 \times 321 + 2.99 \approx 26.11
\]
Final Answer
The prediction for the value of y when x = 321 is approximately 26.11. However, since this value is not among the given options, the correct answer is:
\[
\boxed{D. \text{not meaningful because the x value is outside the scope of the data}}
\]