To find the $x$-intercept and $y$-intercept of the line given by the equation \(3x + 2y = -12\):
To find the \(x\)-intercept, we set \(y = 0\) in the equation \(3x + 2y = -12\) and solve for \(x\):
\[ 3x + 2(0) = -12 \implies 3x = -12 \implies x = \frac{-12}{3} = -4 \]
Thus, the \(x\)-intercept is \(-4\).
To find the \(y\)-intercept, we set \(x = 0\) in the equation \(3x + 2y = -12\) and solve for \(y\):
\[ 3(0) + 2y = -12 \implies 2y = -12 \implies y = \frac{-12}{2} = -6 \]
Thus, the \(y\)-intercept is \(-6\).
The \(x\)-intercept is \(\boxed{-4}\) and the \(y\)-intercept is \(\boxed{-6}\).
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