Questions: Find the x-intercept and y-intercept of the line. 3x + 2y = -12 x-intercept: y-intercept:

Find the x-intercept and y-intercept of the line.
3x + 2y = -12
x-intercept: 
y-intercept:
Transcript text: Find the $x$-intercept and $y$-intercept of the line. \[ 3 x+2 y=-12 \] $x$-intercept: $\square$ $y$-intercept: $\square$
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Solution

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Solution Steps

To find the $x$-intercept and $y$-intercept of the line given by the equation \(3x + 2y = -12\):

  1. $x$-intercept: Set \(y = 0\) in the equation and solve for \(x\).
  2. $y$-intercept: Set \(x = 0\) in the equation and solve for \(y\).
Step 1: Finding the \(x\)-intercept

To find the \(x\)-intercept, we set \(y = 0\) in the equation \(3x + 2y = -12\) and solve for \(x\):

\[ 3x + 2(0) = -12 \implies 3x = -12 \implies x = \frac{-12}{3} = -4 \]

Thus, the \(x\)-intercept is \(-4\).

Step 2: Finding the \(y\)-intercept

To find the \(y\)-intercept, we set \(x = 0\) in the equation \(3x + 2y = -12\) and solve for \(y\):

\[ 3(0) + 2y = -12 \implies 2y = -12 \implies y = \frac{-12}{2} = -6 \]

Thus, the \(y\)-intercept is \(-6\).

Final Answer

The \(x\)-intercept is \(\boxed{-4}\) and the \(y\)-intercept is \(\boxed{-6}\).

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