Transcript text: 4.
$\left.\begin{array}{l}x<0 \\ x \leq-2\end{array}\right)$
Solution
Solution Steps
Step 1: Identify the lines and points on the graph
The graph shows three lines with different slopes and intercepts. The lines intersect at specific points, and some points are marked with open or closed circles.
Step 2: Determine the equations of the lines
The first line passes through the points (-2, 2) and (0, 0). The slope (m) is calculated as:
\[
m = \frac{2 - 0}{-2 - 0} = -1
\]
The equation of the line is \( y = -x \).
The second line passes through the points (0, 0) and (4, -2). The slope (m) is calculated as:
\[
m = \frac{-2 - 0}{4 - 0} = -\frac{1}{2}
\]
The equation of the line is \( y = -\frac{1}{2}x \).
The third line is horizontal and passes through the point (4, -2). The equation of the line is \( y = -2 \).
Step 3: Identify the regions and inequalities
For the line \( y = -x \):
Above the line: \( y > -x \)
Below the line: \( y < -x \)
For the line \( y = -\frac{1}{2}x \):
Above the line: \( y > -\frac{1}{2}x \)
Below the line: \( y < -\frac{1}{2}x \)
For the line \( y = -2 \):
Above the line: \( y > -2 \)
Below the line: \( y < -2 \)
Final Answer
The equations of the lines are:
\( y = -x \)
\( y = -\frac{1}{2}x \)
\( y = -2 \)
The inequalities defining the regions are:
\( y > -x \) and \( y < -x \)
\( y > -\frac{1}{2}x \) and \( y < -\frac{1}{2}x \)