Questions: Using the following conversion factors: 1 mol = MWing(2 d . g) = 6.022 E / 23 molecules = 22.414 L gas at STP How many atoms of Cl are in 347 g of SOCl2(MW=118.96 SOCl2)? (Express final answer as 'atoms Cl')

Using the following conversion factors:
1 mol = MWing(2 d . g) = 6.022 E / 23 molecules = 22.414 L gas at STP
How many atoms of Cl are in 347 g of SOCl2(MW=118.96 SOCl2)? (Express final answer as 'atoms Cl')

Transcript text: Using the following conversion factors: $1 \mathrm{~mol}=\mathrm{MWing}(2 \mathrm{~d} . \mathrm{g})=.6.022 \mathrm{E} / 23$ molecules $=22.414 \mathrm{~L} \mathrm{gas}$ at STP How many atoms of Clare in 347 g of $\mathrm{SOCl}_{2}(\mathrm{MW}=118.96 \mathrm{SOCl} 2$ )? (Express final answer as 'atoms Cl )

Solution

Solution Steps

Step 1: Determine the Moles of $\mathrm{SOCl}_2$

First, we need to calculate the number of moles of $\mathrm{SOCl}_2$ in 347 g. The molar mass (MW) of $\mathrm{SOCl}_2$ is given as 118.96 g/mol.

\[ \text{Moles of } \mathrm{SOCl}_2 = \frac{\text{mass}}{\text{molar mass}} = \frac{347 \, \text{g}}{118.96 \, \text{g/mol}} \]

\[ \text{Moles of } \mathrm{SOCl}_2 = 2.917 \, \text{mol} \]

Step 2: Calculate the Number of Chlorine Atoms

Each molecule of $\mathrm{SOCl}_2$ contains 2 chlorine atoms. Therefore, the number of moles of chlorine atoms is twice the number of moles of $\mathrm{SOCl}_2$.

\[ \text{Moles of Cl atoms} = 2 \times 2.917 \, \text{mol} = 5.834 \, \text{mol} \]

Step 3: Convert Moles of Chlorine Atoms to Number of Atoms

Using Avogadro's number, $6.022 \times 10^{23}$ atoms/mol, we can convert moles of chlorine atoms to the number of atoms.

\[ \text{Number of Cl atoms} = 5.834 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \]

\[ \text{Number of Cl atoms} = 3.513 \times 10^{24} \, \text{atoms} \]