Questions: Factor the following polynomial completely. [ (x-12)^2+11(x-12)-242 ] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. (x-12)^2+11(x-12)-242= B. The polynomial is prime.

Factor the following polynomial completely.
[
(x-12)^2+11(x-12)-242
]

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. (x-12)^2+11(x-12)-242=
B. The polynomial is prime.
Transcript text: Factor the following polynomial completely. \[ (x-12)^{2}+11(x-12)-242 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $(x-12)^{2}+11(x-12)-242=$ $\square$ B. The polynomial is prime.
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Solution

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Solution Steps

To factor the given polynomial completely, we can use substitution to simplify the expression. Let \( y = x - 12 \). This transforms the polynomial into a quadratic in terms of \( y \). We can then factor the quadratic expression using standard techniques such as factoring by grouping or using the quadratic formula. Once factored, we substitute back \( x - 12 \) for \( y \) to get the factorization in terms of \( x \).

Step 1: Substitute and Simplify

Let \( y = x - 12 \). The polynomial can be rewritten as: \[ y^2 + 11y - 242 \]

Step 2: Factor the Quadratic

The quadratic \( y^2 + 11y - 242 \) factors to: \[ (y - 23)(y + 10) \]

Step 3: Substitute Back

Substituting back \( y = x - 12 \), we have: \[ (x - 12 - 23)(x - 12 + 10) = (x - 35)(x - 2) \]

Final Answer

The complete factorization of the polynomial is: \[ \boxed{(x - 35)(x - 2)} \]

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