To solve the given problem, we need to calculate the monthly payment, total payments, and interest for a mortgage. We will use the formula for monthly mortgage payments and then calculate the total payments and interest. For the 15-year mortgage, we will use the same formula with the adjusted term and then calculate the interest saved.
To calculate the monthly payment for a mortgage of \( P = 145500 \) at an annual interest rate of \( r = 7.5\% \) over \( n = 30 \) years, we use the formula:
\[
M = P \cdot \frac{r/n}{1 - (1 + r/n)^{-n \cdot 12}}
\]
Substituting the values, we find:
\[
M = 145500 \cdot \frac{0.075/12}{1 - (1 + 0.075/12)^{-30 \cdot 12}} \approx 1017.36
\]
The total payments over 30 years can be calculated as:
\[
\text{Total Payments} = M \cdot 12 \cdot n = 1017.36 \cdot 12 \cdot 30 \approx 366249.6
\]
The total interest paid over the 30 years is given by:
\[
\text{Interest} = \text{Total Payments} - P = 366249.6 - 145500 \approx 220749.6
\]
For a 15-year mortgage, we use the same formula with \( n = 15 \):
\[
M_{15} = 145500 \cdot \frac{0.075/12}{1 - (1 + 0.075/12)^{-15 \cdot 12}} \approx 1348.8
\]
The total payments for the 15-year mortgage are:
\[
\text{Total Payments}_{15} = M_{15} \cdot 12 \cdot 15 = 1348.8 \cdot 12 \cdot 15 \approx 242784
\]
The interest paid over 15 years is:
\[
\text{Interest}_{15} = \text{Total Payments}_{15} - P = 242784 - 145500 \approx 97284
\]
The interest saved by choosing a 15-year mortgage is:
\[
\text{Interest Saved} = \text{Interest}_{30} - \text{Interest}_{15} = 220749.6 - 97284 \approx 123465.6
\]
- Monthly payment for 30 years: \( \boxed{M_{30} = 1017.36} \)
- Total payments over 30 years: \( \boxed{\text{Total Payments}_{30} = 366249.6} \)
- Interest over 30 years: \( \boxed{\text{Interest}_{30} = 220749.6} \)
- Monthly payment for 15 years: \( \boxed{M_{15} = 1348.8} \)
- Interest saved by choosing a 15-year mortgage: \( \boxed{\text{Interest Saved} = 123465.6} \)